How do you solve #abs(3x-1)>2#?

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Answer 1 · 2015-05-24T09:58:17

Interpreting the modulus in #|3x - 1| > 2# we find:

#3x - 1 > 2# or #3x - 1 < -2#

With the first of these, add #1# to both sides to get:

#3x > 3#

Then divide both sides by #3# to get:

#x > 1#

With the second inequality, add #1# to both sides to get:

#3x < -1#

Then divide both sides by #3# to get:

#x < -1/3#

In summary, the solution is: #x > 1# or #x < -1/3#