How do you solve $| 3 - 2 r | = 7$ $abs(3-2r)=7$ ?

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Answer 1 · 2018-07-11T14:01:48

$r = - 2$ $r=-2$ or $r = 5$ $r=5$

Given that

$| 3 - 2 r | = 7$ $|3-2r|=7$

$3 - 2 r = \pm 7$ $3-2r=\pm7$

$2 r = 3 \pm 7$ $2r=3\pm7$

$r = \frac{1}{2} (3 \pm 7)$ $r=1/2(3\pm 7)$

$r = - 2, 5$ $r=-2, 5$

How do you solve abs(3-2r)=7|3−2r|=7abs(3-2r)=7?