How do you solve #abs(2x-3)>1#?

1 Answer
Jim G.
Mar 7, 2017

#x<1" or "x>2#

Explanation:

For 'greater than' inequalities the solution is always in 2 parts.

#2x-3>1color(red)" or " 2x-3<-1#

Solving both inequalities.

#• 2x-3>1#

add 3 to both sides.

#2xcancel(-3)cancel(+3)>1+3#

#rArr2x>4#

divide both sides by 2

#(cancel(2) x)/cancel(2)>4/2#

#rArrx>2#

#color(red)"OR"#

#• 2x-3< -1#

#rArr2x< 2#

#rArrx<1#

#x<1" or " x>2" is the solution"#

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