How do you solve #abs(16-x)>=10#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Binayaka C. Feb 1, 2017 Solution: #x <= 6 or x >= 26# . In interval notation #(-oo , 6] uu [26 , oo)# Explanation: #|16-x| >=10 or 16-x >= 10 or -x >= -6 or x <= 6# OR #|16-x| >=10 or 16-x <= -10 or -x <= -26 or x >= 26# Solution: #x <= 6 or x >= 26# . In interval notation #(-oo , 6] uu [26 , oo)# [Ans] Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1278 views around the world You can reuse this answer Creative Commons License