How do you solve $abs(1/2x-3)=2$ ?

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Answer 1 · 2018-03-03T07:54:17

See explanation.

First we have to change the equation with absolute value to a set of 2 equations without absolute value.

$|1/2x-3|=2$

is equivalent to:

$1/2x-3=2 vv 1/2x-3=-2$

Now we can solve the both equations:

$1/2x=5 vv 1/2x=1$

$x=10 vv x=2$