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How do you solve a triangle if you are given C = 15 degrees, a = 6.25, b = 2.15?

1 Answer

May 13, 2015

To begin with, side c can be calculated using the cosine formula, cos C= #(a^2+b^2-c^2)/(2ab)#

cos 15= #(6.25^2 +2.15^2 -c^2)/(2(6.25)(2.15)#

c= 4.2101951. Having got side c, get Angle B using the cosine rule again cosB=# (a^2 +c^2-b^2)/(2ac)#

= #(6.25^2 + 4.2101951^2 - 2.15^2)/(2(6.25)(4.2101951)#

B= 7.59499.

Angle A would be !80-B-C= 157.404500

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