How do you solve a triangle if you are given A = 120 degrees, b = 3, c = 10?

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How do you solve a triangle if you are given A = 120 degrees, b = 3, c = 10?

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Answer 1 · 2018-06-21T07:09:37

$color(brown)(c = sqrt139 = 11.79 " units"$

Explanation:

![http://www.mathwarehouse.com/trigonometry/http://law-of-cosines-formula-examples.php](https://useruploads.socratic.org/OgQLU2iVTcGMUvtgaeUI_Law%20of%20cosines.png)

$hat A = 120, b = 3, c = 10, a = ?$

Applying the Law of Cosines,

$a^2 = b^2 + c^2 - 2bc cos A$

$a^2 = 3^2 + 10^2 - (2 * 3 * 10 * cos (120)) = 139$

$color(brown)(c = sqrt139 = 11.79 " units"$

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How do you solve a triangle if you are given A = 120 degrees, b = 3, c = 10?

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