# How do you solve 9e^(5x) = 1269?

Sep 2, 2015

I found: $x = 0.98975$

#### Explanation:

I would rearrange it to get:
${e}^{5 x} = \frac{1269}{9}$
${e}^{5 x} = 141$
take the natural log on both sides:
$\ln \left({e}^{5 x}\right) = \ln \left(141\right)$
and get:
$\cancel{\ln} \left({\cancel{e}}^{5 x}\right) = \ln \left(141\right)$
$5 x = \ln \left(141\right)$
$x = \ln \frac{141}{5} = 0.98975$