How do you solve #9^x=3^(x-2)#?

Question

↳Redirected from "Find the limit as x approaches infinity of #xsin(1/x)#?"

1708 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-03T13:25:31

#x=-2#

We got: #9^x=3^(x-2)#

And so:

#(3^2)^x=3^(x-2)#

#3^(2x)=3^(x-2)#

#2x=x-2#

#2x-x=-2#

#x=-2#