How do you solve #8t + 22< 60#?

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Answer 1 · 2017-12-04T12:36:33

See a solution process below:

First, subtract #color(red)(22)# from each side of the inequality to isolate the #t# term while keeping the inequality balanced:

#8t + 22 - color(red)(22) < 60 - color(red)(22)#

#8t + 0 < 38#

#8t < 38#

Now, divide each side of the inequality by #color(red)(8)# to solve for #t# while keeping the inequality balanced:

#(8t)/color(red)(8) < 38/color(red)(8)#

#(color(red)(cancel(color(black)(8)))t)/cancel(color(red)(8)) < 19/4#

#t < 19/4#