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How do you solve $| 8 - x | = ∣ ∣ \frac{x}{2} + 2 ∣ ∣$ $|8-x|=|x/2+2|$ ?

1 Answer

Jul 20, 2016

${x = 4, x = 20}$ ${x=4,x=20}$

Explanation:

$|8-x|=|x/2+2| ->{(8-x=x/2+2->x=4), (8-x=-x/x-2->x=20):}$

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