How do you solve #8^x – 2 = 3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Bdub Apr 21, 2016 #x=(ln5)/(ln8) ~~0.774# Explanation: #8^x=3+2# #8^x=5# #ln 8^x=ln5# #x ln 8=ln5# #x=(ln5)/(ln8) ~~0.774# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 870 views around the world You can reuse this answer Creative Commons License