How do you solve $\frac{8}{5 x - 4} = \frac{6}{x + 5}$ $8/(5x-4)=6/(x+5)$ ?

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Answer 1 · 2017-06-29T10:59:33

$x \in {\frac{32}{11}}$ $x in {32/11}$

$8 (x + 5) = 6 (5 x - 4)$ $8(x+5) = 6(5x - 4)$

$4 x + 20 = 15 x - 12$ $4x+20 = 15x - 12$

$32 = 11 x$ $32 = 11x$

How do you solve 8/(5x-4)=6/(x+5)85x−4=6x+58/(5x-4)=6/(x+5)?