How do you solve $\frac{8}{3} = \frac{v - 9}{7 v + 4}$ $8/3=(v-9)/(7v+4)$ ?

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How do you solve $\frac{8}{3} = \frac{v - 9}{7 v + 4}$ $8/3=(v-9)/(7v+4)$ ?

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Answer 1 · 2016-09-01T06:53:20

$v = - (\frac{59}{53})$ $v=-(59/53)$

Explanation:

$\frac{8}{3} = \frac{v - 9}{7 v + 4}$ $8/3=(v-9)/(7v+4)$

$8 (7 v + 4) = 3 (v - 9)$ $8(7v+4) = 3(v-9)$
$56 v + 32 = 3 v - 27$ $56v+32 = 3v-27$
$56 v - 3 v = - 27 - 32$ $56v-3v = -27-32$
$53 v = - 59$ $53v=-59$

$v = - (\frac{59}{53})$ $v = -(59/53)$

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How do you solve $\frac{8}{3} = \frac{v - 9}{7 v + 4}$ $8/3=(v-9)/(7v+4)$ ?

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