How do you solve 8 ^(2x) — 5 = 48?

$x = {\log}_{8} \frac{53}{2} \approx 0.95465$
${8}^{2 x} - 5 = 48 | + 5$
${8}^{2 x} = 53 | {\log}_{8} \left(\right)$
2x=log_8(53)|:2
$x = {\log}_{8} \frac{53}{2} \approx 0.95465340909$