How do you solve #8^(-2-x)=431#?

1 Answer
Shwetank Mauria
Feb 5, 2017

#x=-4.9172#

Explanation:

As from definition of log #a^m=b# implies #log_a b=m#

Also #log_a b=logb/loga# where #log# without mentioning base means logarithm to the base #10# and we can get this from tables.

#8^(-2-x)=431# means #log_8 431=-2-x#

or #-2-x=log431/log8=2.6345/0.9031=2.9172#

Hence, #x=-2-2.9172=-4.9172#

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