How do you solve #7x+8<=3x-16#?

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Answer 1 · 2018-03-04T16:02:34

#x<=-6#

#7x+8<=3x-16#

Let start by subtracting #3x# from both sides

#7x + 8 - 3x <= cancel(3x) - 16cancel(-3x)#

#7x + 8 -3x <= -16#

Then subtract #8# from both sides

#7x cancel(+8) - 3x cancel(-8) <=-16 - 8#

#7x - 3x <=-24#

#4x <=-24#

Finally, divide both sides by #4# to find #x#

#(cancel4x)/cancel4<=(-24)/4#

#x<=-6#