# How do you solve 7^(x– 5) = 7^(4x + 7)?

Jul 25, 2015

color(blue)(x=-4

#### Explanation:

7^(x–5)=7^(4x+7)

Here, as the bases are common we can equate the powers to obtain $x$

x–5=4x+7

–5-7=4x -x

$3 x = - 12$

color(blue)(x=-4