How do you solve #7/(b+5)=10/5#?

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Answer 1 · 2016-10-16T08:53:58

#b=-3/5#

Given:#" "7/(b+5)=10/5#

Turn #ul("everything")# upside down so that #b# is in the numerator (top).

#(b+5)/7=5/10#

But #5/10-=1/2#

#(b+5)/7=1/2#

Multiply both sides by 7

#7/7xx(b+5)=7xx1/2#

#b+5=7/2#

Subtract 5 from both sides

#b=7/2-5#

#b=(7-10)/5#

#b=-3/5#