# How do you solve 7 - 2 e ^ x = 5?

$x = 0$
Well it is $7 - 2 {e}^{x} = 5 \implies 7 - 5 = 2 {e}^{x} \implies 2 = 2 {e}^{x} \implies {e}^{x} = 1 \implies x = 0$