How do you solve #6x-2<7# or #8x-2>=3#?
1 Answer
Jul 10, 2015
Solve system:
(1) 6x - 2 < 7
(2)
Explanation:
(1) 6x - 2 < 7 -> 6x < 9 --> x < 3/2
(2)
------------------|0-----------|5/8=========|3/2---------------
Note. The critical point (5/8) is included in the solution set.
Answer by half closed interval: [5/8, 3/2)
