# How do you solve 60,000 = 2^t?

$t = \frac{4 + \log 6}{\log} 2$
log 60000=t log 2, using $\log {a}^{m} = m \log a$.
Use log ab = log a + log b and $\log {10}^{N} = N {\log}_{10} 10 = N X 1 = N$
$t = \frac{\log 6 + \log 10000}{\log} 2 = \frac{\log 6 + \log {10}^{4}}{\log} 2 = \frac{\log 6 + 4}{\log} 2$..