How do you solve #6^(x-3) =52#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Shwetank Mauria May 26, 2016 #x=5.205# Explanation: As #6^(x-3)=52# #(x-3)log6=log52# #x-3=log52/log6=1.716/0.7782=2.205# Hence #x=5.205# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1850 views around the world You can reuse this answer Creative Commons License