How do you solve $[\frac{6}{X - 1}] = [\frac{4}{X + 1}]$ $[6 / (X-1)] = [4 / (X+1)]$ ?

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Answer 1 · 2015-10-12T06:24:17

$x = - 5$ $color(blue)(x=-5$

$\frac{6}{x - 1} = \frac{4}{x + 1}$ $6/(x-1) = 4/(x+1)$

Cross multiplying

$6 \cdot (x + 1) = 4 \cdot (x - 1)$ $6* color(blue)((x+1)) = 4*color(blue)((x-1)$

$6 x + 6 = 4 x - 4$ $6x +6 = 4x-4$

$6 x - 4 x = - 4 - 6$ $6x - 4x = -4-6$

$2 x = - 10$ $2x = -10$

$x = - \frac{10}{2}$ $x=-10/2$

$x = - 5$ $color(blue)(x=-5$

How do you solve [6X−1]=[4X+1][6 / (X-1)] = [4 / (X+1)]?