How do you solve $6\frac{1}{4}+ -9\frac{3}{8}$ ?

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How do you solve $6\frac{1}{4}+ -9\frac{3}{8}$ ?

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Answer 1 · 2018-03-06T20:31:12

$-3 1/8$

Explanation:

Convert the mixed fractions in to improper fractions
$25/4 -75/8$
Try to make it into one fraction
$((25*2) - 75 )/8$
$-25/8$
Then convert it back to a mixed fraction
$-3 1/8$

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How do you solve $6\frac{1}{4}+ -9\frac{3}{8}$ ?

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How do you solve $6\frac{1}{4}+ -9\frac{3}{8}$ ?