How do you solve $\frac{6}{b - 1} = \frac{9}{7}$ $6/(b-1)=9/7$ ?

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How do you solve $\frac{6}{b - 1} = \frac{9}{7}$ $6/(b-1)=9/7$ ?

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Answer 1 · 2017-08-23T00:11:55

B = $\frac{17}{3}$ $17/3$

Explanation:

$\frac{6}{b - 1}$ $6/(b-1)$ = $\frac{9}{7}$ $9/7$
All we have to do is cross multiply
(6)(7) = 9(b - 1)
42 = 9b - 9
Change them side
9b - 9 = 42
9b = 42 + 9
9b = 51
Divide both sides by 9
$\frac{9 b}{9}$ $(9b)/9$ = $\frac{51}{9}$ $51/9$
b = $\frac{17}{3}$ $17/3$
But if they want the answer in decimal, it is b =5.57

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How do you solve $\frac{6}{b - 1} = \frac{9}{7}$ $6/(b-1)=9/7$ ?

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