How do you solve $\frac{6}{10} = \frac{p - 7}{p + 10}$ $6/10=(p-7)/(p+10)$ ?

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Answer 1 · 2018-03-25T06:50:44

The solution is $p = \frac{65}{2}$ $p=65/2$ .

First, reduce the fraction:

$\frac{6}{10} = \frac{p - 7}{p + 10}$ $6/10=(p-7)/(p+10)$

$color(Red)cancelcolor(Black)6^3/color(red)cancelcolor(black)10^5=(p-7)/(p+10)$

$3/5=(p-7)/(p+10)$

$3(p+10)=5(p-7)$

$3*p+3*10=5*p-5*7$

$3p+30=5p-35$

$3p+30color(blue)+color(blue)35=5p-35color(blue)+color(blue)35$

$3p+30color(blue)+color(blue)35=5pcolor(red)cancelcolor(black)(color(black)-35color(blue)+color(blue)35)$

$3p+30color(blue)+color(blue)35=5p$

$3p+65=5p$

$3p+65color(blue)-color(blue)(3p)=5pcolor(blue)-color(blue)(3p)$

$color(red)cancelcolor(black)(3p)+65color(red)cancelcolor(blue)(color(blue)-color(blue)(3p))=5pcolor(blue)-color(blue)(3p)$

$65=5pcolor(blue)-color(blue)(3p)$

$65=2p$

$color(blue)(color(black)65/2)=color(blue)(color(black)(2p)/2)$

$color(blue)(color(black)65/2)=color(blue)(color(black)(color(red)cancelcolor(black)2p)/color(red)cancelcolor(blue)2)$

$color(blue)(color(black)65/2)=p$

This is the solution. Hope this helped!

How do you solve 6/10=(p-7)/(p+10)610=p−7p+106/10=(p-7)/(p+10)?