How do you solve #5x<=2-3x^2#? Precalculus Solving Rational Inequalities Polynomial Inequalities 1 Answer Narad T. Oct 16, 2016 #-2<=x<=1/3# Explanation: #5x<=2-3x^2# Rearranging #3x^2+5x-2<=0# #(3x-1)(x+2)<=0# #x=1/3 or x=-2# #-2<=x<=1/3# Checking, let #x=-1# #-4*1=-4# which #<=0# Answer link Related questions What are common mistakes students make when solving polynomial inequalities? How do I solve a polynomial inequality? How do I solve the polynomial inequality #-2(m-3)<5(m+1)-12#? How do I solve the polynomial inequality #-6<=2(x-5)<7#? How do I solve the polynomial inequality #1<2x+3<11#? How do I solve the polynomial inequality #-12<-2(x+1)<=18#? How do you solve the inequality #6x^2-5x>6#? How do you solve #x^2 - 4x - 21<=0# A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)? How do you solve quadratic inequality, graph, and write in interval notation #x^2 - 8x + 15 >0#? How do you solve #-x^2 - x + 6 < 0#? See all questions in Polynomial Inequalities Impact of this question 1582 views around the world You can reuse this answer Creative Commons License