How do you solve #5x^2+1=-2x^2+1#? Precalculus Linear and Quadratic Functions Completing the Square 1 Answer Noah G Jul 5, 2016 #5x^2 + 2x^2 + 1 - 1 = 0# #7x^2 = 0# #7(x)(x) = 0# #x = 0# Hopefully this helps! Answer link Related questions What does completing the square mean? How do I complete the square? Does completing the square always work? Is completing the square always the best method? Do I need to complete the square if #f(x) = x^2 - 6x + 9#? How do I complete the square if #f(x) = x^2 + 4x - 9#? How do I complete the square if the coefficient of #x^2# is not 1? How do I complete the square if #f(x) = 3x^2 + 12x - 9#? If I know the quadratic formula, why must I also know how to complete the square? How do I use completing the square to describe the graph of #f(x)=30-12x-x^2#? See all questions in Completing the Square Impact of this question 1910 views around the world You can reuse this answer Creative Commons License