How do you solve #5ln x = 35#?

1 Answer
Dec 21, 2015

#x=e^7#

Explanation:

Divide both sides by #5#.

#lnx=7#

Undo the natural logarithm by exponentiating both sides.

#e^(lnx)=e^7#

#x=e^7#

This could also be solved by rewriting #5lnx# using logarithm rules.

#ln(x^5)=35#

#e^(ln(x^5))=e^35#

#x^5=e^35#

#(x^5)^(1/5)=(e^35)^(1/5)#

#x=e^7#