How do you solve #5/( y - 2) = y+2#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Deepak G. Aug 13, 2016 #5/(y-2)=y+2# or #(y-2)(y+2)=5# or #y^2-4=5# or #y^2=5+4# or #y^2=9# or #y=sqrt9# or #y=+-3# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1126 views around the world You can reuse this answer Creative Commons License