How do you solve $-5/(x+3)^2>0$ using a sign chart?

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Answer 1 · 2018-04-07T13:15:28

Please see the explanation below.

Let $f(x)=-5/(x+3)^2$

The domainof definition is $I= (-oo, -3)uu(-3, +oo)$

The question asks for $f(x)>0$

$AA x in I, f(x)<0$

There are no solutions to this inequality

graph{-5/(x+3)^2 [-10, 10, -5, 5]}

How do you solve -5/(x+3)^2>0-5/(x+3)^2>0 using a sign chart?