# How do you solve 5^(n-3) = 1/25?

$\frac{1}{25} = 25 {\setminus}^{- 1} = {\left({5}^{2}\right)}^{- 1} = {5}^{- 2}$.
Comparing with ${5}^{n - 3} , n - 3 = - 2. S o , n = 1$.