# How do you solve 5-log _ 6 (2x - 6) + log _ 6 x = 2?

Mar 19, 2018

5−log_6(2x−6)+log_6x=2

5-2=log_6(2x−6)-log_6x

3=log_6((2x−6)/x) [Since color(red)(loga-logb = log(a/b)]

6^3 = ((2x−6)/x)

(2x−6)=216x

−6=214x

$x = - \frac{3}{107}$