How do you solve #-5( 8b + 8) = - 160#?

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Answer 1 · 2016-11-19T13:35:27

#b = 3#

Step 1) Expand the terms within parenthesis:

#(-5*8b) + (-5*8) = -160#

#-40b - 40 = -160#

Step 2) Solve for #b# while keeping the equation balanced:

#-40b - 40 + 40 = -160 + 40#

#-40b - 0 = -120#

#-40b = -120#

#(-40b)/-40 = -120/(-40)#

#1b = 3#

#b = 3#