How do you solve $\frac{5}{7} = \frac{x - 2}{4}$ $5/7=(x-2)/4$ ?

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Answer 1 · 2018-05-12T15:36:26

try to get rid of the fractions; Solve equation

multiply on both sides with your denominators (4 and 7)

$\frac{5}{7} = \frac{x - 2}{4}$ $5/7 = (x-2)/4$ |*4

$\frac{5 \cdot 4}{7} = (x - 2)$ $(5*4)/7=(x-2)$ |*7

$(5 \cdot 4) = (x - 2) \cdot 7$ $(5*4)=(x-2)*7$

$20 = 7 x - 14$ $20=7x-14$

solve the equation by moving the x-parts to on side and the normal numbers to the other (always move by using the opposite compute-sign)

$20 = 7 x - 14$ $20=7x-14$ |+14

$20 + 14 = 7 x$ $20+14=7x$

$34 = 7 x$ $34=7x$ |:7

$\frac{34}{7} = x$ $34/7=x$

$x = 4 \frac{6}{7}$ $x=4 6/7$

How do you solve 57=x−245/7=(x-2)/4?