How do you solve #5/7 = n /77#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer MeneerNask Mar 1, 2017 You may cross-multiply Explanation: Because #A/B=C/D->BxxC=AxxD# #->7xxn=5xx77# Now divide both sides by 7: #n=5xx11=55# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 1648 views around the world You can reuse this answer Creative Commons License