# How do you solve 5^(4-x)=1/5?

${5}^{4 - x} = \frac{1}{5}$
Since we know that $\frac{1}{5} = {5}^{- 1}$ [This is a rule; $\frac{1}{a} = {a}^{-} 1$]
${5}^{4 - x} = {5}^{- 1}$ Since 5 values are same we can write;
$4 - x = - 1 \implies 4 + 1 = x \implies x = 5$