How do you solve #5^(3-2x)=5^(-x)#?
1 Answer
May 13, 2016
x = 3
Explanation:
Since the bases on both sides of the equation are 5 then the exponents must be equal.
If
#a^m=a^n" then " m=n# Equate the exponents and solve.
hence 3 - 2x = -x → -x = -3 → x = 3
