# How do you solve 5^(3-2x)=5^(-x)?

May 13, 2016

x = 3

#### Explanation:

Since the bases on both sides of the equation are 5 then the exponents must be equal.

If ${a}^{m} = {a}^{n} \text{ then } m = n$

Equate the exponents and solve.

hence 3 - 2x = -x → -x = -3 → x = 3