How do you solve #4x + 7= 13#?

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Answer 1 · 2018-04-30T03:49:22

#x = 3/2# or #1.5#

#4x + 7 = 13#

To solve this, we need to get the variable #x# by itself. To do so, let's move everything else to the other side of the equation:

First, subtract both sides by #color(red)7#:
#4x + 7 quadcolor(red)(-quad7) = 13 quadcolor(red)(-quad7)#

#4x = 6#

Now divide both sides by #color(red)4#:
#(4x)/color(red)4 = 6/color(red)4#

#x = 6/4#

Divide numerator and denominator by #color(red)2#:
#x = 6/4 color(red)(-: 2/2)#

#x = 3/2# or #1.5#

Hope this helps!