How do you solve #4x-3y=14# and #y=-3x+4#?

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Answer 1 · 2015-08-04T05:33:58

The solution for the system of equations is
#color(blue)(x=2,y=-2#

#4x−3y=14#.....equation #(1)#
# y=color(blue)(−3x+4#.....equation #(2)#

Solving by substitution

Substituting equation #2# in equation #1#

#4x−3 * (color(blue)(−3x+4))=14#

#4x +9x -12=14#

#13x =14 +12#

#13x =26#

#color(blue)(x=2#

Finding #y# by substituting #x# in equation #1#

#4x−3y=14#

#4 * 2−3y=14#

#8−3y=14#

#8-14 =3y#

# 3y = -6#

#color(blue)(y=-2#