How do you solve #4x - 12= 2( 2x - 6)#?

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Answer 1 · 2018-05-11T12:47:35

#x = 0#

#4x - 12 = 2(2x - 6)#

RH side:

Distribute (multiply) the 2 to the values in the parenthesis

#12x - 12#

Now lets put it all together

#4x - 12 = 12x - 12#

Add like terms:

Subtract 4 to both sides

#-12 = 8x -12#

Add 12 to both sides

#0 = 8x#

Divide both sides by 8

#x = 0#