How do you solve #4r + 5s - 3t = 9#, #6r - 3s + 1t = 67#, #2r + 0s + 1t = 22#?
1 Answer
Mar 5, 2016
Explanation:
This system of variables is equal to
We can solve it in this way
Finally
#r=(Delta r)/Delta=(-450)/-50=9#
#s=(Delta s)/Delta=150/-50=-3#
#t=(Delta t)/Delta=(-200)/-50=4#