How do you solve 4log_4 74log47?

1 Answer
Gió
May 7, 2015

You can take the 44 in front of the loglog "inside" it as:
log_4(7)^4=log4(7)4=
log_(4)(2401)=log4(2401)=
You can change base to use natural logarithms, that can be evaluated using a pocket calculator, as:
log_(4)(2401)=ln(2401)/ln(4)=5.614log4(2401)=ln(2401)ln(4)=5.614

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