How do you solve $4abs(r+7)+3=59$ ?

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Answer 1 · 2017-03-17T05:04:48

$r=7$ or $r=-21$

As $4|r+7|+3=59$

$4|r+7|=59-3=56$

or $|r+7|=56/4=14$

Now $|r+7|$ stands for modulus or absolute value of $r+7$ . And hence as it is equal to $14$ ,

we either have $r+7=14$ i.e. $r=14-7=7$

or $r+7=-14$ i.e, $r=-14-7=-21$

How do you solve 4abs(r+7)+3=594abs(r+7)+3=59?