# How do you solve 4^x * 3^(2x) = 6 ?

$: . x = \frac{1}{2}$
$\implies {\left(4 \times {3}^{2}\right)}^{x} = 6 = {36}^{\frac{1}{2}}$
$\implies {\left(36\right)}^{x} = {36}^{\frac{1}{2}}$
$: . x = \frac{1}{2}$