How do you solve #4 log x= 4#?

1 Answer
Topscooter
Dec 17, 2015

#x = e#

Explanation:

It's quite simple here, you first divide both sides of the equation by 4, so you now have to solve #ln(x) = 1#, which means that #x = e# because #ln(x) = 1 iff x = e^1 = e# when you apply the exponential function on both sides of the equation (the exponential is a one-on-one function so it guarantees you the solution you will find is unique).

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