How do you solve #4 Log_5 2 + Log_5 X = 3 Log_5 4 - Log_5 3#?

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How do you solve #4 Log_5 2 + Log_5 X = 3 Log_5 4 - Log_5 3#?

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Answer 1 · 2015-12-31T14:00:55

#X=4/3#

Explanation:

#4*log_5 2+log_5 X=3*log_5 4-log_5 3#
#log_5 2^4+log_5 X=log_5 2^(2*3)-log_5 3#
#log_5 (2^4*X) = log_5 (2^6/3)#
#2^4.X=2^6/3#
#X=2^6/(2^4*3)=2^2/3=4/3#

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How do you solve #4 Log_5 2 + Log_5 X = 3 Log_5 4 - Log_5 3#?

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