How do you solve 4/9=(r-3)/6?

1 Answer
Jim G.
Apr 15, 2017

r=17/3

Explanation:

To eliminate the fractions, multiply both sides by the color(blue)"lowest common multiple" (LCM) of 9 and 6

The LCM of 9 and 6 is 18

cancel(18)^2xx4/cancel(9)^1=cancel(18)^3xx((r-3))/cancel(6)^1

rArr8=3(r-3)larrcolor(red)" no fractions"

distribute the bracket.

rArr8=3r-9

add 9 to both sides.

8+9=3rcancel(-9)cancel(+9)

rArr3r=17

divide both sides by 3

(cancel(3) r)/cancel(3)=17/3

rArrr=17/3

color(blue)"As a check"

Substitute this value into the right side of the equation and if equal to the left side then it is the solution.

"right side " =(17/3-9/3)/6=8/3xx1/6=8/18=4/9=" left side"

rArrr=17/3" is the solution"

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