How do you solve #4^ { 3x - 9} - 10= - 3#?

1 Answer
Carl S.
Mar 28, 2018

#x = {log_4(7) + 9}/3 approx 4.4#

Explanation:

#4^{3x -9} - 10 = -3#

#4^{3x -9} = 7# //add 10 to both sides

#3x -9 = log_(4) 7# //#log_4# on both sides (#log_a(a^{x})=x#)

#3x = log_4(7) + 9# //add 9 to both sides

#x = {log_4(7) + 9}/3# //divide both sides by 3

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